а) 4x² - 3 = 0
(2x - √3) (2x + √3) = 0
2x - √3 = 0 ∨ 2x + √3 = 0
2x = √3 ∨ 2x = - √3
х = √3 / 2 ∨ х = - √3 / 2
б) 9x² + 12x + 4 = 0
а = 9, б = 12, с = 4
Δ = b² - 4ac = 12² - 4 * 9 * 4 = 144 - 144 = 0
х = - b / 2a = - 12/18 = - 2/3
в) 2x² + 5x + 3 = 0
а = 2, б = 5, с = 3
Δ = b² - 4ac = 5² - 4 * 2 * 3 = 25 - 24 = 1
√Δ = √1 = 1
x₁ = (- b - √Δ) / 2a = (- 5 - 1) / 4 = - 6/4 = - 3/2 = - 1 1/2 = - 1,5
x₂ = (- b + √Δ) / 2a = (- 5 + 1) / 4 = - 4/4 = - 1
